Question 10.3: Write a balanced equation for the proton-transfer reaction b...
Write a balanced equation for the proton-transfer reaction between phosphate ion (PO_4 ^{3-}) and water, and determine in which direction the equilibrium is favored.
ANALYSIS Look in Table 10.1 to see the relative acid and base strengths of the species involved in the reaction. The acid base proton-transfer equilibrium will favor reaction of the stronger acid and formation of the weaker acid.
ACID | CONJUGATE BASE | ||
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\pmb{Strong acids: 100\% dissociated} \begin{cases} Perchloric acid & HClO_4 \\ Sulfuric acid & H_2SO_4 \\ \\ Hydriodic acid & HI \\ Hydrobromic acid & HBr \\ Hydrochloric acid & HCl \\ Nitric acid & HNO_3 \end{cases} | \left. \begin{matrix} ClO_4 ^- & Perchlorate ion \\ HSO_4 ^- & Hydrogen \\ & sulfate ion \\ I^- & Iodide ion \\ Br^- & Bromide ion \\ Cl^- & Chloride ion \\ NO_3 ^- & Nitrate ion \end{matrix} \right\} \pmb{Little or no reaction as bases} | Increasing base strength |
\pmb{ Hydronium ion } \pmb{ H_3O^+ } | \pmb{ H_2O } \pmb{ Water } | ||
\pmb{Weak acids} \begin{cases} Hydrogen & HSO_4 ^- \\ sulfate ion \\ Phosphoric acid & H_3PO_4 \\ \\ Nitrous acid & HNO_2 \\ Hydrofluoric acid & HF \\ Acetic acid & CH_3COOH \end{cases} | \left. \begin{matrix} SO_4 ^{2-} & Sulfate ion \\ \\ H_2PO_4 ^- & Dihydrogen \\ & phosphate ion \\ NO_2 ^- & Nitrite ion \\ F^- & Fluoride ion \\ CH_3COO^- & Acetate ion \end{matrix} \right\} \pmb{Very weak bases} | ||
\pmb{Very weak acids} \begin{cases} Carbonic acid & H_2CO_3 \\ Dihydrogen & H_2PO_4 ^- \\ phosphate ion \\ Ammonium ion & NH_4 ^+ \\ Hydrocyanic acid & HCN \\ Bicarbonate ion & HCO_3 ^- \\ Hydrogen & HPO_4 ^{2-} \\ phosphate ion \end{cases} | \left. \begin{matrix} HCO_3 ^- & Bicarbonate ion \\ HPO_4 ^{2-} & Hydrogen \\ & phosphate ion \\ NH_3 & Ammonia \\ CN^- & Cyanide ion \\ CO_3 ^{2- } & Carbonate ion \\ PO_4 ^{3-} & Phosphate ion \\ \end{matrix} \right\} \pmb{Weak bases} | ||
\pmb{ Water } \pmb{ H_2O } | \left. \pmb{ OH^- } \pmb{ Hydroxide ion } \right\} \pmb{ Strong base} |
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Phosphate ion is the conjugate base of a weak acid (HPO_4 ^{2-}) and is therefore a relatively strong base. Table 10.1 shows that HPO_4 ^{2-} is a stronger acid than H_2O, and OH^- is a stronger base than PO_4 ^{3-} so the reaction is favored in the reverse direction:
\underset{\pmb{Weaker base}}{PO_4 ^{3-} (aq)} + \underset{\pmb{Weaker acid}}{H_2O(l)}\overset{\rightarrow }{\longleftarrow } \underset{ \pmb{Stronger acid}}{HPO_4 ^{2-}(aq)} + \underset{\pmb{ Stronger base}}{OH^-(aq)}Related Answered Questions
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