Question 14.1: Write the IUPAC name of each alcohol.

Write the IUPAC name of each alcohol.

Strategy
Follow the steps outlined above.
Step 1: Identify the parent chain.

Step 2: Change the ending of the parent alkane from -e to -ol and use a number to show the location of the —OH group.

Step 3: Name and number substituents and list them in alphabetical order.

Step 4: Specify configuration if cis-trans isomerism exists.

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Solution
(a)  The parent alkane is pentane. Number the parent chain from the direction that gives the lower number to the carbon bearing the —OH group. This alcohol is 4-methyl-2-pentanol.

(b)  The parent cycloalkane is cyclohexane. Number the atoms of the ring beginning with the carbon bearing the —OH group as carbon 1 and specify that the methyl and hydroxyl groups are trans to each other. This alcohol is trans-2 methylcyclohexanol.

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