Question : A 0.03-lb bullet traveling at 1300 ft/s strikes the 10-lb wo...

A 0.03-lb bullet traveling at 1300 ft/s strikes the 10-lb wooden block and exits the other side at 50 ft/s as shown. Determine the speed of the block just after the bullet exits the block, and also determine how far the block slides before it stops. The coefficient of kinetic friction between the block and the surface is { \mu }_{ k } = 0.5.

The Blue Check Mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.
\begin{aligned} (\underrightarrow{ + }) \quad\quad & \Sigma m_1 \nu_1 = \Sigma m_2 \nu_2 \\ & (\frac { 0.03 } { 32.2 })(1300)(\frac { 12 } { 13 }) + 0 = (\frac { 10 } { 32.2 })\nu_B + (\frac { 0.03 } { 32.2 })(50)(\frac 4 5) \\ & v_B = 3.48 ft/s \end{aligned} \\ T_1 + \Sigma U_{ 1 – 2 } = T_2 \\ \frac 1 2 (\frac { 10 } { 32.2 })(3.48)^2 – 5(d) = 0
Screenshot_2020-11-07 Engineering Mechanics Dynamics (14th Edition) Instructors Solutions Manual by Russell C Hibbeler (z-l[...](16)