A \frac{1}{2}-in-diameter water pipe is 60 ft long and delivers water at 5 gal/min at 20°C. What fraction of this pipe is taken up by the entrance region?
A \frac{1}{2}-in-diameter water pipe is 60 ft long and delivers water at 5 gal/min at 20°C. What fraction of this pipe is taken up by the entrance region?
Convert
Q = (5 gal/min)\frac{0.00223 ft^3/s}{1 gal/min} = 0.0111 ft^3/s
The average velocity is
V = \frac{Q}{A} = \frac{0.0111 ft^3/s}{(\pi/4) [(\frac{1}{2}/12) ft]^2} = 8.17 ft/s
From Table 1.4 read for water \nu = 1.01 \times 10^{-6} m^2/s = 1.09 \times 10^{-5} ft^2/s. Then the pipe Reynolds number is
Re_d = \frac{Vd}{\nu} = \frac{(8.17 ft/s)[(\frac{1}{2}/12) ft]}{1.09 \times 10^{-5} ft^2/s} = 31,300Table 1.4 Viscosity and Kinematic Viscosity of Eight Fluids at 1 atm and 20°C | |||||
Fluid | µ, kg/(m·s)^† |
Ratio µ/µ(H_2) |
ρ, kg/m^3 |
v, m^2/s^† | Ratio v/v(Hg) |
Hydrogen | 9.0 E-6 | 1.0 | 0.084 | 1.05 E-4 | 910 |
Air | 1.8 E-5 | 2.1 | 1.20 | 1.50 E-5 | 130 |
Gasoline | 2.9 E-4 | 33 | 680 | 4.22 E-7 | 3.7 |
Water | 1.0 E-3 | 114 | 998 | 1.01 E-6 | 8.7 |
Ethyl alcohol | 1.2 E-3 | 135 | 789 | 1.52 E-6 | 13 |
Mercury | 1.5 E-3 | 170 | 13,550 | 1.16 E-7 | 1.0 |
SAE 30 oil | 0.29 | 33,000 | 891 | 3.25 E-4 | 2,850 |
Glycerin | 1.5 | 170,000 | 1,260 | 1.18 E-3 | 10,300 |
^†1 kg/(m·s) = 0.0209 slug/(ft·s); 1 m^2/s = 10.76 ft^2/s.
This is greater than 4000; hence the flow is fully turbulent, and Eq. (6.6) applies for entrance length:
\frac{L_e}{d} \approx 1.6 Re_d^{1/4} for Re_d \leq 10^7 (6.6)
\frac{L_e}{d} \approx 1.6 Re_d^{1/4} = (1.6)(31,300)^{1/4} = 21The actual pipe has L/d = (60 ft)/[(\frac{1}{2}/12)ft] = 1440. Hence the entrance region takes up the fraction
\frac{L_e}{L} = \frac{21}{1440} = 0.015 = 1.5%
This is a very small percentage, so that we can reasonably treat this pipe flow as essentially fully developed.