Question : A 10 kVA, 500/100 V transformer has the following circuit pa...

A 10 kVA, 500/100 V transformer has the following circuit parameters referred to primary:
Equivalent resistance, R_{eq}=0.3\: ohm; Equivalent reactance, X_{eq}=5.2\: ohm. When supplying power to a lagging load, the current, power and voltage measured on primary side were 20 A, 8 kW and 500 V, respectively. Calculate the voltage on the secondary terminals under these conditions. Draw the relevant phasor diagram.

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Rating of transformer =10\: KVA=10*10^{3}\: VA

 

Power factor on primary side,

cos\: \phi _{1}=\frac{P}{V_{1}I_{1}}=\frac{8*10^{3}}{500*20}=0.8\: kg

 

\therefore sin\: \phi _{1}=sin\: cos^{-1}\: 0.8=0.6

 

Primary induced emf, E_{1}=V_{1}-I_{1}R_{ep}\: cos\: \phi _{1}-I_{1}\: X_{ep}\: sin\: \phi _{1}

 

=sin\: 500-20*0.3*0.8-20*5.2*0.6=432.8\: V

 

Transformation ratio, K=\frac{100}{500}=0.2

 

Secondary induced emf, E_{2}=E_{1}*K=432.8*0.2=86.56\: V

 

Secondary terminal voltage on load,

V_{2}=E_{2}=86.56\: V (since all the parameters are referred to primary side)

The equivalent circuit and phasor diagram is shown in Fig. 2.42(b).

fig 2.42