A 10 V rms signal with a frequency of 1 kHz is applied to a 10 mH coil with a negligible winding resistance.Determine the reactive power (P_{r}).
Question 13.15: A 10V rms signal with a frequency of 1 kHz is applied to a 1...
First, calculate the inductive reactance and current values,
X_{L}= 2\pi fL= 2\pi (1 \ kHz)(10 \ mH)= 62.8 \ \OmegaI= \frac{V_{s}}{X_{L}}= \frac{10 \ V}{62.8 \ \Omega } = 159 \ mA
Then, use Equation 13-18 : P_{r}= I^{2}_{rms}X_{L}.
P_{r}= I^{2}X_{L}= (159 \ mA)^{2}(62.8 \ \Omega )= 1.59 \ VARRelated Answered Questions
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