Question : A 20-lb block slides down a 30° inclined plane with an initi...

A 20-lb block slides down a 30° inclined plane with an initial velocity of 2 ft/s. Determine the velocity of the block in 3 s if the coefficient of kinetic friction between the block and the plane is { \mu }_{ k } = 0.25.

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(+\nwarrow )\quad \quad m{ (v }_{ v' })+\Sigma \int _{ { t }_{ 1 } }^{ { t }_{ 2 } }{ { F }_{ { y }' }dt } =m{ (v }_{ y' })_{ 2 }\\ 0+N(3)-20\cos { { 30 }^{ \circ }(3) } =0\quad \quad N=17.32lb\\ (+\swarrow )\quad \quad m{ (v }_{ x' })_{ 1 }+\Sigma \int _{ { t }_{ 1 } }^{ { t }_{ 2 } }{ { F }_{ { x' } }dt } =m{ (v }_{ x' })_{ 2 }\\ \frac { 20 }{ 32.2 } \left( 2 \right) +20\sin { { 30 }^{ \circ } } (3)-0.25(17.32)(3)=\frac { 20 }{ 32.2 } v\\ v=29.4ft/s
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