A 230 V, 50 Hz voltage is applied to the primary of a 4:1step-down transformer used in a bridge rectifier having a load resistance of 600 Ω. Assuming the diodes to be ideal, determine (a) d.c. output voltage, (b) d.c. power delivered to the load, (c) PIV, and (d) output frequency.

Question

A 230 V, 50 Hz voltage is applied to the primary of a 4:1 step-down transformer used in a bridge rectifier having a load resistance of 600 Ω. Assuming the diodes to be ideal, determine (a) d.c. output voltage, (b) d.c. power delivered to the load, (c) PIV, and (d) output frequency.

Accepted Answer

(a) The rms value of the transformer secondary voltage,

[latex]V_{rms} =\frac{230}{4}[/latex] = 57.5 V

The maximum value of the secondary voltage

[latex]V_{m} =\sqrt{2}[/latex] × 57.5 = 81.3 V

Therefore, d.c. output voltage,

[latex]V_{d.c.} =\frac{2V_{m}}{\pi}=\frac{2 × 81.3}{\pi}[/latex] = 52 V

(b) The d.c. power delivered to the load,

[latex]P_{d.c.} =\frac{V_{d.c.}^{ 2}}{R_{L}}=\frac{52^{2}}{1000}[/latex] = 2.704 W

(c) PIV across each diode = [latex]V_{m}[/latex] = 81.3 V
(d) Output frequency = 2 × 50 = 100 Hz

Question 18.16: A 230 V, 50 Hz voltage is applied to the primary of a 4:1ste...

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