Question 3.11: A 500 g sample of dry soil was used for a combined sieve and...

A 500 g sample of dry soil was used for a combined sieve and hydrometer analysis (152 H type hydrometer). The soil mass passing through the 75 μ sieve = 120 g. Hydrometer analysis was carried out on a mass of 40 g that passed through the 75 μ sieve. The average temperature recorded during the test was 30°C.

Given: \left.G_{s}=2.55, C_{m} \text { (meniscus }\right)=0.50, C_{o}=+2.5, \mu=8.15 \times 10^{-3} poises.

The actual hydrometer reading R_{a}=15.00 after a lapse of 120 min after the start of the test. Determine the particle size D and percent finer P^{\prime} \% \text { and } P \%.

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From Eq. (3.29)

 

L=16.3-0.1641 R (3.29)

 

L=16.3-0.1641 R

 

where, R=R_{a}+C_{m}=15.0+0.5=15.5

 

L=16.3-0.1641 \times 15.5=13.757

 

From Eq. (3.24)

 

D=\sqrt{\frac{30 \mu}{\left(G_{s}-1\right) \gamma_{w}}} \sqrt{\frac{L}{t}}=K \sqrt{\frac{L}{t}} (3.24)

 

D=\sqrt{\frac{30 \times 8.15 \times 10^{-6}}{2.55-1}} \times \sqrt{\frac{13.757}{120}}=0.0043 mm

 

From Eq. (3.32)

 

P^{\prime}=\frac{C_{s g} R_{c}}{M_{s}} \times 100

 

Percent finer, P^{\prime} \%=\frac{C_{s g} R_{c}}{M_{s}} \times 100

 

From Table 3.7, C_{s g}=1.02 \text { for } G_{s}=2.55

 

From Table 3.6, C_{T}=+3.8 \text { for } T=30^{\circ} C

 

Now, R_{c}=R_{a}-C_{o}+C_{T}=15-2.5+3.8=16.3

 

Now, P^{\prime}=\frac{1.02 \times 16.3}{40} \times 100=41.57 \%

 

P \%=41.57 \times \frac{120}{500} \approx 10 \%

 

Table 3.6 Temperature correction factors C_{T}
Temp °C C_{T} Temp °C C_{T}
15 -1.1 23 0.7
16 -0.9 24 1
17 -0.7 25 1.3
18 -0.5 26 1.65
19 -0.3 27 2
20 0 28 2.5
21 0.2 29 3.05
22 0.4 30 3.8

 

Table 3.7 Correction factors C_{s g} for unit weight of solids
G_{s} of soil solids Correction factor C_{s g} G_{s} of soil solids  Correction factor C_{s g}
2.85 0.96 2.65 1.00
2.80 0.97 2.60 1.01
2.75 0.98 2.55 1.02
2.70 0.99 2.50 1.04

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