A 60 mm diameter shaft running in a bearing carries a load of 2000 N. If the coefficient of friction between the shaft and bearing is 0.03, find the power transmitted when it runs at 1440 r.p.m.

Question

Accepted Answer

Given : d = 60 mm or r = 30 mm = 0.03 m ; W = 2000 N ; [latex]\mu =0.03[/latex] ;N = 1440 r.p.m. or [latex]\omega =2\pi imes [/latex] 1440/60 = 150.8 rad/s

We know that torque transmitted,

[latex]T=\mu \cdot W\cdot r[/latex]= 0.03 × 2000 × 0.03 = 1.8 N-m

[latex] herefore [/latex] Power transmitted, P = T.[latex]\omega [/latex] = 1.8 × 150.8 = 271.4 W

Question : A 60 mm diameter shaft running in a bearing carries a load o...