Question 14.EP.1: A catalog lists the basic dynamic load rating for a ball bea...

In Equation (14_1), \frac{L_{2}}{L_{1}}=\left(\frac{P_{1}}{P_{2}}\right)^{k}

P_{1}=C=7050 \mathrm{lb}       (basic dynamic load rating)

P_{2}=P_{d}=3500 \mathrm{lb}       (design load)

L_{1}=10^{6} \mathrm{rev}        (L_{10} life at load C)

k = 3               (ball bearing)

Then letting the life, L_{2}, be called the design life,L_{d}. at the design load, L_{2}=L_{d}=L_{1}\left(\frac{P_{1}}{P_{2}}\right)^{k}=10^{6}\left(\frac{7050}{3500}\right)^{3.00}=8.17 \times 10^{6} \mathrm{rev}  This must be interpreted as the L_{10} life at a load of 3500 Ib.