A circuit is needed to give an output of 1 when any of its three inputs are 0. Draw the truth table for this circuit and state what single gate could implement this circuit. Then derive its dual and state which gives the most appropriate desription of the circuit’s operation.
Question 1.27: A circuit is needed to give an output of 1 when any of its t...
The truth table, which clearly describes the NAND function, is shown in Fig. 1.19 together with the single gate capable of implementing this function, and its dual.
| A | B | C | Y |
| 0 | 0 | 0 | 1 |
| 0 | 0 | 1 | 1 |
| 0 | 1 | 0 | 1 |
| 0 | 1 | 1 | 1 |
| 1 | 0 | 0 | 1 |
| 1 | 0 | 1 | 1 |
| 1 | 1 | 0 | 1 |
| 1 | 1 | 1 | 0 |
The NAND based circuit shows the output is active-LOW if all of the inputs are active-HIGH, whereas the OR based circuit shows the output is active-HIGH if any of the inputs are active-LOW. The OR based circuit is the most appropriate given the stated circuit requirements.
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