A closed barrel has as its curved surface the surface obtained by rotating about the x-axis the part of the curve
y = a[ 2 − cosh(x/a) ]
lying in the range −b ≤ x ≤ b, where b<a \cosh^{−1} 2. Show that the total surface area, A, of the barrel is given by
A = \pia[ 9a − 8a exp(−b/a) + a exp(−2b/a) − 2b ].