Question 15.sp.1: (a) Draw a skeletal structure of gadoleic acid, CH3(CH2)9CH ...

(a) Draw a skeletal structure of gadoleic acid, CH_{3}(CH_{2})_{9}CH\overline{—}CH(CH_{2})_{7}COOH, a 20-carbon fatty acid obtained from fish oils. (b) Label the hydrophobic and hydrophilic portions. (c) Predict how its melting point compares to the melting points of arachidic acid and arachidonic acid (Table 15.2).

Mp (°C) Name Structure Number of C=C’s ber of C’s
Saturated Fatty Acids
44 Lauric acid CH_{3}(CH_{2})_{10}COOH 0 12
58 Myristic acid CH_{3}(CH_{2})_{12}COOH 0 14
63 Palmitic acid CH_{3}(CH_{2})_{14}COOH 0 16
71 Stearic acid CH_{3}(CH_{2})_{16}COOH 0 18
77 Arachidic acid CH_{3}(CH_{2})_{18}COOH 0 20
Unsaturated Fatty Acids
1 Palmitoleic acid CH_{3}(CH_{2})_{5}CH\overline{—} CH(CH_{2})_{7}COOH 1 16
16 Oleic acid CH_{3}(CH_{2})_{7}CH\overline{—} CH(CH_{2})_{7}COOH 1 18
-5 Linoleic acid CH_{3}(CH_{2})_{4}CH\overline{—}CHCH_{2}CH\overline{—} CH(CH_{2})_{7}COOH 2 18
-11 Linolenic acid CH_{3}CH_{2}CH\overline{—}CHCH_{2}CH\overline{—}CHCH_{2}CH\overline{—}CH(CH_{2})_{7}COOH 3 18
-49 Arachidonic acid CH_{3}(CH_{2})_{4}(CH\overline{—} CHCH_{2})_{4}(CH_{2})_{2}COOH 4 20

Analysis

• Skeletal structures have a carbon at the intersection of two lines and at the end of every line.
The double bond must have the cis arrangement in an unsaturated fatty acid.
• The nonpolar C—C and C—H bonds comprise the hydrophobic portion of a molecule and the
polar bonds comprise the hydrophilic portion.
• For the same number of carbons, increasing the number of double bonds decreases the melting
point of a fatty acid.

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a. and b. The skeletal structure for gadoleic acid is drawn below. The hydrophilic portion is the COOH group and the hydrophobic portion is the rest of the molecule.

c. Gadoleic acid has one cis double bond, giving it a lower melting point than arachidic acid (no double bonds), but a higher melting point than arachidonic acid (four double bonds).

15.1

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