A force of 300 lbf moves a truck with 40 mi/h up a hill. What is the power?
A force of 300 lbf moves a truck with 40 mi/h up a hill. What is the power?
=12000 \times \frac{1609.3 \times 3.28084}{3600} \frac{ lbf – ft }{ s }
=17600 \frac{ lbf – ft }{ s }=22.62 Btu / s