Question 3.14: A furnace burns a liquid coal tar fuel derived from coke-ove...

A furnace burns a liquid coal tar fuel derived from coke-ovens. Calculate the heat transferred in the furnace if the combustion gases leave at 1500 K. The burners operate with 20 per cent excess air. Take the fuel supply temperature as 50ºC (323 K) and the air temperature as 15ºC (288 K).

The properties of the fuel are:

Carbon        87.5 per cent w/w

Hydrogen        8.0

Oxygen        3.5

Nitrogen        1.0

Sulphur      trace

Ash      balance

Net calorific value        39,540 kJ/kg

Latent heat of vaporisation        350 kJ/kg

Heat capacity        1.6 kJ/kg K

\ C^{º}_{p} of gases, kJ/kmol K

\ C_{p} =A+BT+CT^{2} +DT^{3}

D C B A Camponent
17.125E-9 -5.518E-5 7.332E-2 19.763 1    \ CO_{2}
-3.591E-9 10.538E-6 19.207E-4 32.190 2    \ H_{2}O 
-10.634E-9 17.431E-6 -3.674E-6 28.06 3    \ O_{2}
-11.662E-9 26.752E-2 -1.354E-2 31.099 4    \ N_{2}

 

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Material balance

Basis: 100 kg (as analysis is by weight).

Assume complete combustion: maximum heat release.

Reactions: \ C+O_{2} \rightarrow CO_{2}

\ H_{2} +\frac{1}{2}O_{2} \rightarrow CO_{2}
Element kg kmol Stoichiometric  kmol kmol, products
C 87.5 7.29 7.29 7.29,\CO_{2}
\ H_{2} 8.0 4.0 2.0 4.0,\ H_{2}O
\ O_{2} 3.5 0.11 0.11
\ N_{2} 1.0 0.04 0.04
Total 11.44 9.29

\ O_{2} required with 20 per cent excess = 9.29×1.2=11.15 kmol.

Unreacted \ O_{2}   from combustion air = 11.15-9.29=1.86 kmol.

\ N_{2} with combustion air = \ 11.15\times \frac{79}{21}=41.94
Composition of combustion gases:

\ CO_{2} =7.29kmol

\ H_{2}O=4.0

\ O_{2} 0.11+1.86=1.97

\ N_{2} 0.04+41.98

Presentation of data to the program:

\ C_{p} of fuel (component 5), taken as constant,

A=1.6,  B = C= D = 0

Heat of reaction and latent heat, taken to be values at datum temperature of 298 K. There is no need to convert to kJ/kmol, providing quantities are expressed in kg. For the purposes of this example the dissociation of CO_{2} and H_{2}O at 1500 K is ignored.

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