Question 4.43: A load of 7.5 kW at 230 V is supplied by a short-shunt cumul...

A load of 7.5 kW at 230 V is supplied by a short-shunt cumulatively compound D C generator. If the armature, series and shunt field resistances are 0.4,0.3 and 100 ohm respectively. Calculate the induced emf and the load resistance.

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\text { Refer to Fig. } 4.66

 

I_{L}=\frac{7 \cdot 5 \times 1000}{230}=32 \cdot 61 A

 

I_{s h}=\frac{V+I_{L} R_{s e}}{R_{s h}}=\frac{230+32 \cdot 61 \times 0 \cdot 3}{100}=2 \cdot 39 A

 

I_{a}=I_{L}+I_{s h}=32 \cdot 61+2.39=35 A

 

\text { Induced emf, } \quad E_{g}=V+I_{L} R_{s e}+I_{a} R_{a}

 

=230+32 \cdot 61 \times 0.3+35 \times 0.4= 2 5 3 \cdot 7 8 V

 

\text { Load resistance, } R_{L}=\frac{V^{2}}{P}=\frac{(230)^{2}}{7 \cdot 5 \times 1000}=7 \cdot 053 \text { ohm }

 

 

4.43

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