Question 4.211E: A mass-loaded piston/cylinder containing air is at 45 lbf/in...

A mass-loaded piston/cylinder containing air is at 45 lbf / in .^{2}, 60 F with a volume of 9 ft ^{3}, while at the stops V = 36 ft ^{3}. An air line, 75 lbf / in .^{2}, 1100 R, is connected by a valve, as shown in Fig. P4.154. The valve is then opened until a final inside pressure of 60 lbf / in .^{2} is reached, at which point T = 630 R. Find the air mass that enters, the work, and heat transfer.

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C.V. Cylinder volume.

Continuity Eq.4.20:    m _{2}- m _{1}= m _{ in }

Energy Eq.4.21:    m _{2} u _{2}- m _{1} u _{1}= m _{ in } h _{\text {line }}+{ }_{1} Q _{2}-{ }_{1} W _{2}

Process:    P _{1}  is constant to stops, then constant V to state 2 at  P _{2}

State 1:  P _{1}, T _{1}            m _{1}=\frac{ P _{1} V }{ RT _{1}}=\frac{45 \times 9 \times 144}{53.34 \times 519.7}=2.104   lbm

 

State 2:     Open to:      P _{2}=60   lbf / in ^{2}, T _{2}=630   R

Table F.5:

\begin{array}{l}h _{ i }=266.13   btu / lbm \\u _{1}=88.68   Btu / lbm \\u _{2}=107.62   Btu / lbm\end{array}

 

{ }_{1} W _{2}=\int PdV = P _{1}\left( V _{\text {stop }}- V _{1}\right)=45 \times(36-9) \frac{144}{778}= 2 2 4 . 9   Btu

 

m _{2}= P _{2} V _{2} / RT _{2}=60 \times 36 \times 144 /(53.34 \times 630)=9.256   lbm

 

m _{ i }= m _{2}- m _{1}=9.256-2.104=7.152   lbm

 

\begin{aligned}{ }_{1} Q _{2} &= m _{2} u _{2}- m _{1} u _{1}- m _{ i } h _{ i }+{ }_{1} W _{2} \\&=9.256 \times 107.62-2.104 \times 88.68-7.152 \times 266.13+224.9 \\&=- 8 6 8 . 9   Btu\end{aligned}

 

………………………………….

Eq.4.20: \left(m_{2}-m_{1}\right)_{ C.V. }=\sum m_{i}-\sum m_{e}

Eq.4.21:

\begin{aligned}E_{2}-E_{1}=Q_{ C.V. }-W_{ C.V. } &+\sum m_{i}\left(h_{i}+\frac{1}{2} V _{i}^{2}+g Z_{i}\right) \\&-\sum m_{e}\left(h_{e}+\frac{1}{2} V _{e}^{2}+g Z_{e}\right)\end{aligned}
1
F.5.1
F.5.2

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