Question 14.35: A pair of crossed helical gears connects shafts making angle...

A pair of crossed helical gears connects shafts making angle of 45°. The right-hand pinion has 36 teeth and a helix angle of 20°. The right-hand gear has 48 teeth and its module in the normal plane is 2.5 mm. Determine (a) The helix angle of the gear, (b) circular pitch in the normal plane, (c) module of the pinion in its plane of rotation, (d) module of the gear in its plane of rotation, and (e) centre distance.

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\text { Given: } z_{1}=36, z_{2}=48, m_{n}=2.5 mm , \Sigma=45^{\circ}, \beta_{1}=20^{\circ} .

(a)  \Sigma=\beta_{1}+\beta_{2}=45^{\circ}, \beta_{2}=45-20=25^{\circ} .

(b)  p_{n}=\pi m_{n}=\pi \times 2.5=7.854 mm .

(c)  m_{t 1}=m_{n} / \cos \beta_{1}=2.5 / \cos 20^{\circ}=2.66 mm .

m_{t 2}=m_{n} / \cos \beta_{2}=2.5 / \cos 25^{\circ}=2.758 mm .

(d)  C =0.5 m_{n}\left[z_{1} / \cos \beta_{1}+z_{2} / \cos \beta_{2}\right] .

=0.5 \times 2.5\left[36 / \cos 20^{\circ}+36 / \cos 25^{\circ}\right] .

= 114.1 mm.

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