Asimplified schematic of the dc motor is shown in Fig. 10.11. The armature winding (only one turn of the winding is shown in Fig. 10.11) is placed within a uniform magnetic field of flux density B. The resistance of the winding is R and its inductance is L .When the input voltage e_{i} is applied, current i flows in the armature winding. Under these conditions (a current-carrying conductor within a magnetic field), force F_{e} is exerted on both the top and the bottom sections of the armature winding as illustrated in Fig. 10.11. The force F_{e} is given by Eq. (10.4),
F_{e} = ilB
where l is the length of the armature coil. Because the winding is free to rotate around its longitudinal axis, force F _{e} produces a torque:
T_{e} = F_{e} r . (10.19)
This torque acts on each (top and bottom) section of each turn in the armature winding.
Assuming that there are N turns in the winding and they are all within the uniform magnetic field, the total induced torque exerted on the armature winding is
T_{e} =2N F_{e} r . (10.20)
When Eq. (10.20) is compared with the equation for a rotational–electromechanical transducer given in Fig. 10.2, the coupling coefficient for the dc motor can be identified as
\alpha_{r}=\frac{1}{2NlBr} , (10.21)
and hence the electrically induced torque can be expressed as
T_{e} =\frac{1}{\alpha_{r} } i . (10.22)
When the armature winding starts to rotate within a uniform magnetic field, voltage e _{m} is induced in the winding, given by Eq. (10.6):
e_{m}= vBl .
Replacing translational velocity v with the rotational velocity Ω times radius r and accounting for N turns and two sections of each turn in the armature winding, one finds that the total voltage induced is
e_{m}= 2N\Omega rBl (10.23)
or
e_{m} =\frac{1}{\alpha_{r} } \Omega (10.24)
where \alpha_{r} is the coupling coefficient defined by Eq. (10.21). Equations (10.22) and (10.24) describe mathematically the coupling between mechanical and electrical parts of the system and are often called the coupling equations.