Products
Rewards 
from HOLOOLY

We are determined to provide the latest solutions related to all subjects FREE of charge!

Please sign up to our reward program to support us in return and take advantage of the incredible listed offers.

Enjoy Limited offers, deals & Discounts by signing up to Holooly Rewards Program

HOLOOLY 
BUSINESS MANAGER

Advertise your business, and reach millions of students around the world.

HOLOOLY 
TABLES

All the data tables that you may search for.

HOLOOLY 
ARABIA

For Arabic Users, find a teacher/tutor in your City or country in the Middle East.

HOLOOLY 
TEXTBOOKS

Find the Source, Textbook, Solution Manual that you are looking for in 1 click.

HOLOOLY 
HELP DESK

Need Help? We got you covered.

Chapter 15

Q. 15.23

A reinforced concrete pile 30 ft long and 15 in. in diameter is embedded in a saturated clay of very stiff consistency. Laboratory tests on samples of undisturbed soil gave an average undrained cohesive strength c_{u}=2500 lb / ft ^{2}. Determine the net pullout capacity and the allowable pullout load with F_{s}=3.

Step-by-Step

Verified Solution

Given: L = 30 ft, d = 15 in. diameter, c_{u}=2500 lb / ft ^{2}, F_{s}=3.

From Fig. 15.23 c_{a} / c_{u}=0.41 \text { for } c_{u}=2500 \times 0.0479 \approx 120 kN / m ^{2} for concrete pile.

From Eq. (15.66)

 

P_{u l}=W_{p}+A_{s} \alpha \bar{c}_{u} (15.66)

 

P_{u l}(\text { net })=\alpha \bar{c}_{u} A_{s}

 

where \alpha=c_{a} / c_{u}=0.41, c_{u}=2500 lb / ft ^{2}

 

A_{s}=3.14 \times \frac{15}{12} \times 30=117.75 ft ^{2}

 

Substituting

 

P_{u l}(\text { net })=\frac{0.41 \times 2500 \times 117.75}{1000}=120.69 kips

 

P_{u l} \text { (allowed) }=\frac{120.69}{3} \approx 40 \text { kips }