A sample of saturated clay from a consolidometer test has a total weight of 3.36 Ib and a dry weight of 2.32 Ib: the specific gravity of the solid particles is 2.7. For this sample, determine the water content, void ratio, porosity and total unit weight.
Question 3.4: A sample of saturated clay from a consolidometer test has a ...
w=\frac{W_{w}}{W_{s}} \times 100 \%=\frac{3.36-2.32}{2.32}=44.9 \% \approx 45 \%
e=\frac{w G_{s}}{S}=\frac{0.45 \times 2.7}{1}=1.215
n=\frac{e}{1+e}=\frac{1.215}{1+1.215}=0.548 \text { or } 54.8 \%
\gamma_{t}=\frac{\gamma_{w}\left(G_{s}+e\right)}{1+e}=\frac{62.4(2.7+1.215)}{1+1.215}=110.3 lb / ft ^{3}
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