Question 19.1: A set of three bolts is to be used to provide a clamping for...

A set of three bolts is to be used to provide a clamping force of 12 000 lb between two components of a machine. The load is shared equally among the three bolts. Specify suitable bolts, including the grade of the material, if each is to be stressed to 75% of its proof strength. Then compute the required tightening torque.

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The load on each screw is to be 4000 lb. Let’s specify a bolt made from SAE Grade 5 steel, having a proof strength of 85 000 psi. Then the allowable stress is
\sigma_a = 0.75(85 000 psi) = 63 750 psi
The required tensile stress area for the bolt is then

A_t=\frac{\text{load}}{\sigma_a}=\frac{4000lb}{63750lb/in^2}=0.0627in^2

From Table 19–4(B), we find that the 3/8–16 UNC thread has the required tensile stress area. The required tightening torque will be
T = KDP = 0.15(0.375 in)(4000 lb) = 225 lb . in

 

TABLE 19–4 American Standard Screw Threads
B. American Standard thread dimensions, fractional sizes
Basic major
diameter, D
(in)
Coarse threads: UNC Fine threads: UNF
Size—Threads per inch, n Tensile stress area (in{}^2) Size—Threads per inch, n Tensile stress area (in{}^2)
0.2500 1/4-20 0.0318 1/4-28 0.0364
0.3125 5/16-18 0.0524 5/16-24 0.058
0.3750 3/8-16 0.0775 3/8-24 0.0878
0.4375 7/16-14 0.1063 7/16-20 0.1187
0.5000 1/2-13 0.1419 1/2-20 0.1599
0.5625 9/16-12 0.182 9/16-18 0.203
0.6250 5/8-11 0.226 5/8-18 0.256
0.7500 3/4-10 0.334 3/4-16 0.373
0.8750 7/8-9 0.462 7/8-14 0.509
1.000 1-8 0.606 1-12 0.663
1.125 1\frac{1}{8}-7 0.763 1\frac{1}{8}-12 0.856
1.125 1\frac{1}{4}-7 0.969 1\frac{1}{4}-12 1.073
1.375 1\frac{3}{8}-6 1.155 1\frac{3}{8}-12 1.315
1.500 1\frac{1}{2}-6 1.405 1\frac{1}{2}-12 1.581
1.750 1\frac{3}{4}-5 1.90
2.000 2-4\frac{1}{2} 2.50

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