A shunt generator supplies 195 A at 220 V. Armature resistance is 0.02 ohm, shunt field resistance is 44 ohm. If the iron and friction losses amount to 1600 watt, find (i) emf generated; (ii) copper losses; (iii) b.h.p. of the engine driving the generator.
Question 4.46: A shunt generator supplies 195 A at 220 V. Armature resistan...
The conventional circuit is shown in Fig.4.78.
Shunt field current,
I_{s h}=\frac{V}{R_{s h}}=\frac{220}{44}=5 AArmature current, \quad I_{a}=I_{L}+I_{s h}=195+5=200 A
Generated or induced emf,
E_{g}=V+I_{a} R_{a}=220+200 \times 0.02=224 VArmature copper loss:
=I_{a}^{2} R_{a}=(200)^{2} \times 0.02=800 W\begin{array}{l}\begin{array}{l}\text { Shunt field copper loss }=I_{s h}^{2} R_{s h}=(5)^{2} \times 44=1100 W \\\text { Total copper losses }=800+1100=1900 W \\\text { Output power }=V I_{L}=220 \times 195=42900 W \\\text { Input power }=42900+1600+1900=46400 W\end{array}\\\text { B.H.P. of the engine driving the generation }=\frac{46400}{735.5}=63.08 \text { H.P.}\end{array}
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