Question 13.5: A tank circuit has a capacitor of 100 pF and an inductor of ...

Given L = 100 μH, C = 100 pF and R = 5Ω

(a) The resonant frequency,           f_{O} =\frac{1}{2\pi \sqrt{LC} }= \frac{1}{2\pi \sqrt{100\times 10^{-6}\times 100\times 10^{-12} } }= 1592   MHz

(b) The impedance of resonance,  Z_{o} =\frac{L}{CR}= \frac{100\times 10^{-6} }{100\times 10^{-12}\times 5 } = 200  K \Omega

(c) The quality factor,                      Q =\frac{2\pi f_{O} L}{R}= \frac{2\pi \times 1592\times 10^{3}\times 100\times 10^{-6}}{5} = 200

(d) The bandwidth,                           BW =\frac{f_{O} }{Q}= \frac{1592\times 10^{3} }{200} = 7.96  KHz