Question 3.1: A tensile force of 9500 N is applied to a 12-mm-diameter rou...

Machine Elements in Mechanical Design [EXP-45119]

A tensile force of 9500 N is applied to a 12-mm-diameter round bar, as shown in Figure 3_6. Compute the direct tensile stress in the bar.

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Objective Compute the tensile stress in the round bar.

Given Force = F = 9500 N; diameter = D = 12 mm.

Analysis Use the direct tensile stress formula. Equation (3-1): $\sigma =F/A$ . Compute the cross-sectional area from $A=\pi D^{2} /4$ .

Results $A=\pi D^{2} /4 =\pi \left(12mm\right) ^{2}/4=113mm^{2}$

\sigma=F / A=(9500 \mathrm{~N}) /\left(113 \mathrm{~mm}^{2}\right)=84.0 \mathrm{~N} / \mathrm{mm}^{2}=84.0 \mathrm{MPa}

Comment The results are shown on stress element A in Figure 3_6 . which can be taken to be anywhere within the bar because, ideally, the stress is uniform on any cross section. The cube form of the element is as shown in Figure 3-5 (a) $T=P/n$ .

3_6

3_5a

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