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Question 9.92: A transmission line has a series impedance of Z = 100 ∠75° Ω...

A transmission line has a series impedance of {Z}=100 \angle 75^{\circ} \Omega and a shunt admittance of {Y}=450 \angle 48^{\circ} \mu \mathrm{S}. Find:

(a) the characteristic impedance {Z}_{o}=\sqrt{\mathbf{Z} / {Y}}

(b) the propagation constant \gamma=\sqrt{{Z}{Y}}.

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(a) Z_{o}=\sqrt{\frac{Z}{Y}}=\sqrt{\frac{100 \angle 75^{\circ}}{450 \angle 48^{\circ} \times 10^{-6}}}={471.4 \angle 13.5^{\circ} \Omega}\\\\
(b) \gamma=\sqrt{Z Y}=\sqrt{100 \angle 75^{\circ} \times 450 \angle 48^{\circ} \times 10^{-6}}={0.2121 \angle 61.5^{\circ}}

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