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Question 2.131: A welded connection is in equilibrium under the action of th...

A welded connection is in equilibrium under the action of the four forces shown. Knowing that { F }_{ A } = 8 kN and { F }_{ B } = 16 kN, determine the magnitudes of the other two forces.

Question Data is a breakdown of the data given in the question above.
  • F_A = 8 kN
  • F_B = 16 kN
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Step 1:
To find the value of Fc, we can use the given informati...
Step 2:
Using the equation ΣFx = 0, we can set up an equation t...
Step 3:
Substituting the given values, we have: (3/5)(16 kN)...
Step 4:
Simplifying this equation, we get: (48/5) kN - Fc - ...
Step 5:
Combining like terms, we have: (24/5) kN - Fc = 0
Step 6:
To isolate Fc, we can subtract (24/5) kN from both side...
Step 7:
Simplifying this, we find: Fc = 4.80 kN
Therefore, the value of Fc is 4.80 kN.

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