Question 5.16: At a particular site lies a layer of fine sand 8 m thick bel...

At a particular site lies a layer of fine sand 8 m thick below the ground surface and having a void ratio of 0.7. The GWT is at a depth of 4 m below the ground surface. The average degree of saturation of the sand above the capillary fringe is 50%. The soil is saturated due to capillary action to a height of 2.0 m above the GWT level. Assuming G_{s}=2.65, calculate the total effective pressures at depths of 6 m and 3 m below the ground surface.

The Blue Check Mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.
\gamma_{d}=\frac{G_{s} \gamma_{w}}{1+e}=\frac{2.65 \times 9.81}{1.7}=15.29 kN / m ^{3}

 

\gamma_{ sat }=\frac{\left(e+G_{s}\right) \gamma_{w}}{1+e}=\frac{(0.7+2.65) \times 9.81}{1.7}=19.33 kN / m ^{3}

 

\gamma_{b}=\gamma_{ sat }-\gamma_{w}=19.33-9.81=9.52 kN / m ^{3}

 

The moist unit weight of soil above the capillary fringe is

 

\gamma_{m}=\frac{\left(G_{s}+e S\right) \gamma_{w}}{1+e}=\frac{(2.65+0.7 \times 0.5) \times 9.81}{1.7}=17.31 kN / m ^{3}

 

Capillary pressure,

 

u_{c}=n h_{c} \gamma_{w}=\frac{e}{1+e} h_{c} \gamma_{w}=\frac{0.7}{1.7} \times 2 \times 9.81=8.08 kN / m ^{2}

 

Effective stresses at different levels

(a) At ground level \sigma^{\prime}=0

(b) Overburden pressure at fringe level =\sigma_{o}^{\prime}=\overline{h_{c}} \gamma_{m}=2 \times 17.31=34.62 kN / m ^{2}

(c) Effective pressure at fringe level =\sigma_{c}^{\prime}=\sigma_{o}^{\prime}+u_{c}=34.62+8.08=42.70 kN / m ^{2}

(d) Effective pressure at GWT level =\sigma_{\text {sat }}^{\prime}=\sigma_{c}^{\prime}+\sigma_{d}^{\prime}=42.70+2 \times 15.29

 

=42.70+30.58=73.28 kN / m ^{2}

 

(e) Effective pressure at 6 m below GL

\sigma_{t}^{\prime}=\sigma_{\text {sat }}^{\prime}+h_{w} \gamma_{b}=73.28+2 \times 9.52=73.28+19.04=92.32 kN / m ^{2}

 

Effective stress at a depth 3 m below GL

Refer Fig. Ex. 5.16.

 

\sigma_{z}^{\prime}=\sigma_{o}^{\prime}+u_{c}+\left(z-h_{c}\right) \gamma_{d}=34.62+8.08+(3-2) \times 15.29 \approx 58 kN / m ^{2}
5.16

Related Answered Questions