Question 8.1: Calculate the density of a mixture of methanol and water at ...

Calculate the density of a mixture of methanol and water at 20ºC, composition 40 per cent w/w methanol.

Density of water at 20^{\circ} C 998.2 kg / m ^{3}

Density of methanol at 20^{\circ} C 791.2 kg / m ^{3}

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Basis: 1000 kg

 

\text { Volume of water }=\frac{0.6 \times 1000}{998.2}=0.601 m ^{3}

 

\text { Volume of methanol }=\frac{0.4 \times 1000}{7912}=0.506 m ^{3}

 

\text { Total } 1.107 m ^{3}

 

\text { Density of mixture }=\frac{1000}{1.107}=903.3 kg / m ^{3}

 

Experimental value = 934.5 kg / m ^{3}

 

\text { Error }=\frac{934.5-903.3}{903.3}=\begin{array}{c}3 \text { per cent, which would be acceptable for most } \\\text { engineering purposes }\end{array}

 

If data on the variation of density with temperature cannot be found, they can be approximated for non-polar liquids from Smith’s equation for thermal expansion (Smith et al., 1954).

 

\beta=\frac{0.04314}{\left(T_{c}-T\right)^{0.641}} (8.2)

 

where β = coefficient of thermal expansion, K ^{-1},

T_{c} = critical temperature, K,

T = temperature, K.

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