Calculate the number of moles of nitric acid in 325 mL of 16 M HNO_3 solution.
Question 14.9: Calculate the number of moles of nitric acid in 325 mL of 16...
Step 1:
Substitute the given data into the equation. In this case, we have a volume of 0.325 liters and we need to find the number of moles of HNO3. So, we have:
moles = 0.325 liters × M
Step 2:
We are given that the molarity of HNO3 is 16 mol HNO3 / 1 liter. So, we can substitute this value into the equation:
moles = 0.325 liters × (16 mol HNO3 / 1 liter)
Step 3:
Simplify the equation by canceling out the units of liters:
moles = (0.325 liters) × (16 mol HNO3 / 1)
Step 4:
Multiply the numerical values:
moles = 5.2 mol HNO3
Therefore, the number of moles of HNO3 in 0.325 liters is 5.2 mol HNO3.
Final Answer
READ Knowns V = 325 mL
16 M HNO_3 solution
PLAN Use the equation moles = liters \times M
CALCULATE moles= (0.325 \cancel{L}) (\frac{16 mole HNO_3}{1 \cancel{L}} )=5.2 mol HNO_3
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