Question 8.20: Consider an ideal stationary magnetic dipole m in a static e...

Consider an ideal stationary magnetic dipole m in a static electric field E. Show that the fields carry momentum

p =-\epsilon_{0} \mu_{0}( m \times E )                               (8.45)

[Hint: There are several ways to do this. The simplest method is to start with p =\epsilon_{0} \int( E \times B ) d \tau, \text { write } E =-\nabla V , and use integration by parts to show that 

p =\epsilon_{0} \mu_{0} \int V J d \tau .

So far, this is valid for any localized static configuration. For a current confined to an infinitesimal neighborhood of the origin we can approximate V (r) V (0) E(0) · r. Treat the dipole as a current loop, and use Eqs. 5.82 and 1.108. ]^{21}

\oint d l ^{\prime}= 0                                   (5.82)

\oint( c \cdot r ) d l = a \times c                                (1.108)

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p =\epsilon_{0} \int_{ \nu }( E \times B ) d \tau=-\epsilon_{0} \int_{ \nu }( \nabla V) \times B d \tau=-\epsilon_{0} \int_{ \nu }[ \nabla \times(V B )-V \nabla \times B ] d \tau

 

=\epsilon_{0} \oint_{ S } V B \times d a +\epsilon_{0} \mu_{0} \int_{\nu } V J d \tau=\frac{1}{c^{2}} \int_{ \nu } V J d \tau.

(I used Problem 1.61(b) in the penultimate step. Here ν is all of space, and S is its surface at infinity, where B = 0, so the surface integral vanishes.) Using V( r ) \approx V( 0 )+( \nabla V) \cdot r =V( 0 )- E ( 0 ) \cdot r ,

p =\frac{1}{c^{2}} V( 0 ) \int J d \tau-\frac{1}{c^{2}} \int[ E ( 0 ) \cdot r ] J d \tau .

For a current loop,  \int J d \tau \rightarrow \int I d l=I \int d l = 0 , and (Eq. 1.108):

\int[ E ( 0 ) \cdot r ] J d \tau \rightarrow \int[ E ( 0 ) \cdot r ] I d l=I \int[ E ( 0 ) \cdot r ] d l =I a \times E ( 0 )= m \times E .

So

p =-\frac{1}{c^{2}}( m \times E ) .

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