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Question 9.1: Derivation of the Efficiency of the Carnot Cycle Show that t...

Derivation of the Efficiency of the Carnot Cycle

Show that the thermal efficiency of a Carnot cycle operating between the temperature limits of T_{H} \text { and } T_{L} is solely a function of these two temperatures and is given by Eq. 9–2.

\eta_{ th , Carnot }=1-\frac{T_{L}}{T_{H}}

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