Question 2.3: Determine (1) the moment of the force F about point C; and (...

Determine (1) the moment of the force F about point C; and (2) the perpendicular distance between C and the line of action of F.

The Blue Check Mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

Part 1

The moment of a force about point C can be computed by either the scalar method (M_{C} = Fd), or the vector method (M_{C} =r×F). In this problem the scalar method would be inconvenient, because we have no easy means of determining d (the perpendicular distance between C and the line AB). Therefore, we use the vector method, which consists of the following three steps: (1) write F in vector form; (2) choose an r, and write it in vector form; and (3) compute M_{C} =r × F.

Step 1: Write F in vector form.Referring to the figure, we obtain

F=500\lambda_{AB}=500\frac{\overrightarrow{AB} }{\left|\overrightarrow{AB} \right| }=500\left(\frac{2i − 4j + 3k}{5.385} \right)

which yields

 

F=185.7i − 371.4j + 278.6k N

 

Step 2: Choose an r, and write it in vector form. The vector r is a vector from point C to any point on the line of action of F. From the figure we see that there are two convenient choices for r—the vector from point C to either point A or point B. As shown in the figure, let us choose r to be r_{CA}. (As an exercise, you may wish to solve this problem by choosing r to be the vector from point C to point B.) Now we have

 

r=r_{CA}= −2i m

 

Step 3: Calculate M_{C} = r × F. The easiest method for evaluating the cross product is to use the determinant expansion:

M_{C} =r × F=r_{CA} × F=\left|\begin{matrix} i & j & k \\ -2 & 0 & 0 \\ 185.7 & -371.4 & 278.6 \end{matrix} \right|

Expanding this determinant gives

M_{C} =557.2j + 742.8k N · m

Part 2

The magnitude of M_{C} is

M_{C}=\sqrt{(557.2)^{2} + (742.8)^{2}}= 928.6 N · m

The perpendicular distance d from point C to the line of action of F may be determined by

d=\frac{M_{C}}{F}=\frac{928.6}{500}=1.857m

Observe that, instead of using the perpendicular distance to determine the moment, we have used the moment to determine the perpendicular distance.Caution A common mistake is choosing the wrong sense for r in Eq. (2.4) M_{o}=r × F Note that r is directed from the moment center to the line of action of F. If the sense of r is reversed, r × F will yield the correct magnitude of the moment, but the wrong sense. To avoid this pitfall, it is strongly recommended that you draw r on your sketch before attempting to write it in vector form.

Related Answered Questions

The force F and point A lie in the xy-plane. Probl...