Determine (1) the moment of the force F about point C; and (2) the perpendicular distance between C and the line of action of F.
Determine (1) the moment of the force F about point C; and (2) the perpendicular distance between C and the line of action of F.
Part 1
The moment of a force about point C can be computed by either the scalar method (M_{C} = Fd), or the vector method (M_{C} =r×F). In this problem the scalar method would be inconvenient, because we have no easy means of determining d (the perpendicular distance between C and the line AB). Therefore, we use the vector method, which consists of the following three steps: (1) write F in vector form; (2) choose an r, and write it in vector form; and (3) compute M_{C} =r × F.
Step 1: Write F in vector form.Referring to the figure, we obtain
F=500\lambda_{AB}=500\frac{\overrightarrow{AB} }{\left|\overrightarrow{AB} \right| }=500\left(\frac{2i − 4j + 3k}{5.385} \right)which yields
F=185.7i − 371.4j + 278.6k N
Step 2: Choose an r, and write it in vector form. The vector r is a vector from point C to any point on the line of action of F. From the figure we see that there are two convenient choices for r—the vector from point C to either point A or point B. As shown in the figure, let us choose r to be r_{CA}. (As an exercise, you may wish to solve this problem by choosing r to be the vector from point C to point B.) Now we have
r=r_{CA}= −2i m
Step 3: Calculate M_{C} = r × F. The easiest method for evaluating the cross product is to use the determinant expansion:
M_{C} =r × F=r_{CA} × F=\left|\begin{matrix} i & j & k \\ -2 & 0 & 0 \\ 185.7 & -371.4 & 278.6 \end{matrix} \right|Expanding this determinant gives
M_{C} =557.2j + 742.8k N · m
Part 2
The magnitude of M_{C} is
M_{C}=\sqrt{(557.2)^{2} + (742.8)^{2}}= 928.6 N · mThe perpendicular distance d from point C to the line of action of F may be determined by
d=\frac{M_{C}}{F}=\frac{928.6}{500}=1.857mObserve that, instead of using the perpendicular distance to determine the moment, we have used the moment to determine the perpendicular distance.Caution A common mistake is choosing the wrong sense for r in Eq. (2.4) M_{o}=r × F Note that r is directed from the moment center to the line of action of F. If the sense of r is reversed, r × F will yield the correct magnitude of the moment, but the wrong sense. To avoid this pitfall, it is strongly recommended that you draw r on your sketch before attempting to write it in vector form.