Determine the Laplace transform of f (t )=u(t −a)−u(t −b).
Determine the Laplace transform of f (t )=u(t −a)−u(t −b).
Because we know L[u(t −a)] = e^{−as}/s, we can use the linearity of the Laplace transform to find
L[u(t −a)−u(t −b)] = \frac {1}{s} e^{−as} − \frac {1}{s} e^{−bs} = \frac {1}{s} (e^{−as} −e^{−bs} )