Determine the maximum output voltage for the RL integrator in Figure 20-35 when a single pulse is applied as shown. The rheostat is set so that the total resistance is 50 Ω.

Question

Accepted Answer

Calculate the time constant.

[latex] au = \frac{L}{R}= \frac{100 \ mH}{50 \ \Omega }= 2 \ ms[/latex]

Because the pulse width is 5 ms, the inductor charges for [latex]2.5 au [/latex]. Use the exponential formula derived from Equation 13-8:[latex]v=V_{F}+ (V_{i}- V_{F})e^{-Rt/L }[/latex] ,with [latex]V_{i}[/latex]= 0 and [latex] au = L/R [/latex] to calculate the voltage.

[latex]v_{out(max)}= V_{F}(1-e^{-t/ au })= 25(1-e^{-5ms/2ms})[/latex]

[latex] \ \ \ \ \ \ \ \ \ \ \ \ \ \ =25(1-e^{-2.5})= 25(1-0.082)= 25(0.918)= 22.9 \ V[/latex]

Question 20.6: Determine the maximum output voltage for the RL integrator i...

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