Question 7.18: Determine the output voltage of the temperature-measuring br...

Determine the output voltage of the temperature-measuring bridge circuit in Figure 7-49 if the thermistor is exposed to a temperature of 50°C and its resistance at 25°C is 1.0 kΩ. Assume the resistance of the thermistor decreases to 900 Ω at 50°C.

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\Delta R_{them}= 1.0 \ k\Omega – 900 \ \Omega = 100 \ \Omega

 

\Delta V_{OUT} \cong \Delta R_{them}\left(\frac{V_{S}}{4 \ R} \right)= 100 \ \Omega \left(\frac{12 \ V}{4 \ k\Omega } \right)= 0.3 \ V

Since V_{OUT}= 0 V when the bridge is balanced at 25°C and it changes 0.3 V, then

V_{OUT} = 0.3 V

when the temperature is 50°C.

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