Question 14.sp.3: Draw the α isomer of the cyclic form of D-galactose.

[1] Draw a hexagon with an O atom in the upper right corner. Add the $CH_{2}OH$ above the ring on the first carbon to the left of the O atom.

[2] Draw the new chirality center on the first carbon clockwise from the O atom.
• The α isomer has the OH group drawn down, while a β isomer has the OH group drawn up.

[3] Add the OH groups and H atoms to the three remaining carbons (C2–C4).
• Groups on the right side in the acyclic form are drawn down, below the six-membered ring,and groups on the left side in the acyclic form are drawn up, above the six- membered ring.