Question 1.9: Effect of Piston Weight on Pressure in a Cylinder The piston...

Effect of Piston Weight on Pressure in a Cylinder The piston of a vertical piston–cylinder device containing a gas has a mass of 60 kg and a cross-sectional area of 0.04 m², as shown in Fig. 1–54. The local atmospheric pressure is 0.97 bar, and the gravitational acceleration is 9.81 m/s². (a) Determine the pressure inside the cylinder. (b) If some heat is transferred to the gas and its volume is doubled, do you expect the pressure inside the cylinder to change?

Question Data is a breakdown of the data given in the question above.
  • Piston mass: 60 kg
  • Piston cross-sectional area: 0.04 m²
  • Local atmospheric pressure: 0.97 bar
  • Gravitational acceleration: 9.81 m/s²
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Step 1:
Determine the pressure inside the cylinder (Part a) To calculate the pressure inside the cylinder, we need to consider the atmospheric pressure and the weight of the piston.
Step 2:
Drawing the free-body diagram We start by drawing a free-body diagram of the piston. The forces acting on the piston are the atmospheric pressure (PA) and the weight of the piston (W).
Step 3:
Substituting the given values, we can rewrite the equation as: PA = Patm A + mg where Patm is the atmospheric pressure, A is the cross-sectional area of the piston, m is the mass of the piston, and g is the gravitational acceleration.
Step 4:
Calculating the pressure inside the cylinder Using the given values (Patm = 0.97 bar, A = 0.04 m², m = 60 kg, and g = 9.81 m/s²), we can calculate the pressure inside the cylinder: PA = 0.97 bar +(60 kg)(9.81 m/s²) / (0.04 m²) [(1N/(1 kg⋅m/s²))(1 bar)/(10⁵ N/m²)] = 1.12 bar Therefore, the pressure inside the cylinder is 1.12 bar.
Step 6:
Determining the effect of volume change on pressure (Part b) The volume change will have no effect on the free-body diagram drawn in part (a), as it only considers the atmospheric pressure and the weight of the piston. Therefore, the pressure inside the cylinder will remain the same even if the volume is doubled.
In conclusion, the pressure inside the cylinder is 1.12 bar, and doubling the volume will not change this pressure.

Final Answer

A gas is contained in a vertical cylinder with a heavy piston. The pressure inside the cylinder and the effect of volume change on pressure are to be determined.
Assumptions Friction between the piston and the cylinder is negligible. Analysis (a) The gas pressure in the piston–cylinder device depends on the atmospheric pressure and the weight of the piston. Drawing the free-body diagram of the piston as shown in Fig. 1–54 and balancing the vertical forces yield

P A=P_{ atm } A+W

Solving for P and substituting,

\begin{aligned}P &=P_{ atm }+\frac{m g}{A} \\&=0.97 bar +\frac{(60 kg )\left(9.81 m / s ^{2}\right)}{\left(0.04 m ^{2}\right)}\left(\frac{1 N }{1 kg \cdot m / s ^{2}}\right)\left(\frac{1 bar }{10^{5} N / m ^{2}}\right) \\&=1.12 \text { bar }\end{aligned}

(b) The volume change will have no effect on the free-body diagram drawn in part (a), and therefore the pressure inside the cylinder will remain the same.
Discussion If the gas behaves as an ideal gas, the absolute temperature doubles when the volume is doubled at constant pressure.

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