Question 12.1: Entangled states. The singlet spin configuration (Equation 1...

Entangled states. The singlet spin configuration (Equation 12.1) is the classic example of an entangled state—a two-particle state that cannot be expressed as the product of two one-particle states, and for which, therefore, one cannot really speak of “the state” of either particle separately. You might wonder
whether this is somehow an artifact of bad notation—maybe some linear combination of the one-particle states would disentangle the system. Prove the following theorem:

\frac{1}{\sqrt{2}}(|\uparrow \downarrow\rangle-|\downarrow \uparrow\rangle)              (12.1).

Consider a two-level system, \left|\phi_{a}\right\rangle \text { and }\left|\phi_{b}\right\rangle, \text { with }\left\langle\phi_{i} \mid \phi_{j}\right\rangle=\delta_{i j} \text { (For example, }\left|\phi_{a}\right\rangle might represent spin up and \left|\phi_{b}\right\rangle spin down.) The two-particle state

\alpha\left|\phi_{a}(1)\right\rangle\left|\phi_{b}(2)\right\rangle+\beta\left|\phi_{b}(1)\right\rangle\left|\phi_{a}(2)\right\rangle ,

\text { (with } \alpha \neq 0 \text { and } \beta \neq 0 \text { ) } cannot be expressed as a product

\left|\psi_{r}(1)\right\rangle\left|\psi_{s}(2)\right\rangle ,

for any one-particle states \left|\psi_{r}\right\rangle \text { and }\left|\psi_{s}\right\rangle .

Hint: Write \left|\psi_{r}\right\rangle \text { and }\left|\psi_{s}\right\rangle \text { as linear combinations of }\left|\phi_{a}\right\rangle \text { and } \mid \phi_{b} \text { ) } .

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Suppose, on the contrary, that

\alpha\left|\phi_{a}(1)\right\rangle\left|\phi_{b}(2)\right\rangle+\beta\left|\phi_{b}(1)\right\rangle\left|\phi_{a}(2)\right\rangle=\left|\psi_{r}(1)\right\rangle\left|\psi_{s}(2)\right\rangle ,

for some one-particle states \left|\psi_{r}\right\rangle \text { and }\left|\psi_{s}\right\rangle \text {. Because }\left|\phi_{a}\right\rangle \text { and }\left|\phi_{b}\right\rangle constitute a complete set of one-particle states (this is a two-level system), any other one-particle state can be expressed as a linear combination of them. In particular,

\left|\psi_{r}\right\rangle=A\left|\phi_{a}\right\rangle+B\left|\phi_{b}\right\rangle, \quad \text { and } \quad\left|\psi_{s}\right\rangle=C\left|\phi_{a}\right\rangle+D\left|\phi_{b}\right\rangle ,

for some complex numbers A, B, C, and D. Thus

\alpha\left|\phi_{a}(1)\right\rangle\left|\phi_{b}(2)\right\rangle+\beta\left|\phi_{b}(1)\right\rangle\left|\phi_{a}(2)\right\rangle=\left[A\left|\phi_{a}(1)\right\rangle+B\left|\phi_{b}(1)\right\rangle\right]\left[C\left|\phi_{a}(2)\right\rangle+D\left|\phi_{b}(2)\right\rangle\right] .

=A C\left|\phi_{a}(1)\right\rangle\left|\phi_{a}(2)\right\rangle+A D\left|\phi_{a}(1)\right\rangle\left|\phi_{b}(2)\right\rangle+B C\left|\phi_{b}(1)\right\rangle\left|\phi_{a}(2)\right\rangle+B D\left|\phi_{b}(1)\right\rangle\left|\phi_{b}(2)\right\rangle .

(i) Take the inner product with \left\langle\phi_{a}(1)\right|\left\langle\phi_{b}(2)\right|: \quad \alpha=A D .

(ii) Take the inner product with \left\langle\phi_{a}(1)\right|\left\langle\phi_{a}(2)\right|: \quad 0=A C .

(iii) Take the inner product with \left\langle\phi_{b}(1)\right|\left\langle\phi_{a}(2)\right|: \quad \beta=B C .

(iv) Take the inner product with \left\langle\phi_{b}(1)\right|\left\langle\phi_{b}(2)\right|: \quad 0=B D .

\text { (ii) } \Rightarrow \text { either } A=0 \text { or } C=0 \text {. But if } A=0, \text { then (i) } \Rightarrow \alpha=0 ,    which is excluded by assumption, whereas if C=0 \text {, then (iii) } \Rightarrow \beta=0 , which is likewise excluded. Conclusion: It is impossible to express this state as a product of one-particle states. QED

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