Estimate the size of hydrocyclone needed to separate 90 per cent of particles with a diameter greater than 20 μm, from 10 $m ^{3} / h$ of a dilute slurry.

Physical properties: solid density 2000 $kg / m ^{3}$ , liquid density 1000 $kg / m ^{3}$ , viscosity 1 mN $s / m ^{2}$

Question

Estimate the size of hydrocyclone needed to separate 90 per cent of particles with a diameter greater than 20 μm, from 10 [latex]m ^{3} / h[/latex] of a dilute slurry.

Physical properties: solid density 2000 [latex]kg / m ^{3}[/latex], liquid density 1000 [latex]kg / m ^{3}[/latex], viscosity 1 mN [latex]s / m ^{2}[/latex]

Accepted Answer

[latex] ext { Flow-rate }=\frac{10 imes 10^{3}}{60}=166.71 / min[/latex]

[latex]\left( ho_{s}- ho_{L} ight)=2.0-1.0=1.0 g / cm ^{3}[/latex]

From Figure 10.22, for 90 per cent removal of particles above 20 μm

[latex]d_{50}=14 \mu m[/latex]

[latex] ext { From Figure } 10.23 ext {, for } \mu=1 mN s / m ^{2},\left( ho_{s}- ho_{L} ight)=1.0 g / cm ^{3}, L=167 / min[/latex]

[latex]D_{c}=16 cm[/latex]

Question 10.2: Estimate the size of hydrocyclone needed to separate 90 per ...

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