Flow in a Porous Medium
with an Impervious “Hole” (COMSOL)
Here, we solve the problem of two-dimensional flow of water of viscosity \mu (at a temperature T=293.15 \mathrm{~K} ) in the rectangular region ABCD of the porous medium shown in Fig. 14.1(a), in which there is a central circular region E of essentially zero permeability, which allows no flow through it. The boundaries AB and CD are also impervious to flow.
The pressure along the two ends, AD and BC, are p=10 and p=0 \mathrm{psig}, respectively. The dimensions of the rectangle are length L=2 \mathrm{~m} and height H=1 \mathrm{~m}, and the radius R of the circle is 0.3 \mathrm{~m}. Both the rectangle and circle are centered on the origin (0,0). The porosity of the medium is \varepsilon=0.175, and its constant permeability is \kappa=93 darcies, or 0.917 \times 10^{-10} \mathrm{~m}^{2} (see Eqn. (4.32) for the conversion factor).
1 darcy =1 \frac{\mathrm{cm} / \mathrm{s} \mathrm{cP}}{\mathrm{atm} / \mathrm{cm}} \doteq 0.986 \times 10^{-8} \mathrm{~cm}^{2}=1.06 \times 10^{-11} \mathrm{ft}^{2}. (4.32)
Let p denote the pressure, x and y the coordinates, and \mathbf{v} the velocity vector. From Darcy’s law (pages 207-208) and continuity (Eqn. (5.51)), we have:
\nabla \cdot \mathbf{v}=0. (5.51)
\mathbf{v}=-\frac{\kappa}{\mu} \nabla p, \quad \nabla \cdot \mathbf{v}=0, (14.1)
Substitution of \mathbf{v} from Darcy’s law into the continuity equation gives us (for constant \kappa and \mu, which can then be eliminated) Laplace’s equation:
\nabla^{2} p=\frac{\partial^{2} p}{\partial x^{2}}+\frac{\partial^{2} p}{\partial y^{2}}=0. (14.2)
Thus, we shall use COMSOL to solve Laplace’s equation for the pressure.