Flow Patterns in a Lake (COMSOL)
Fig. E7.4.1 shows a bird’s-eye view of a lake whose shape is approximated by merging two ellipses and two rectangles. These rectangles protrude to the “west” at \mathrm{AB} and to the “south” at \mathrm{CD}, and can serve as an inlet and an outlet to and from the lake, respectively.
Note that the inviscid flow (possibly with rotation) is governed by Poisson’s equation:
-\nabla^{2} \psi=-\left(\frac{\partial^{2} \psi}{\partial x^{2}}+\frac{\partial^{2} \psi}{\partial y^{2}}\right)=f, (E7.4.1)
in which \psi is the stream function. In COMSOL, Eqn. (E7.4.1) is represented as \nabla \cdot(-c \nabla u)=f, where u=\psi and c=1 in our case.
For two-dimensional flow, it can readily be shown that -\nabla^{2} \psi=\zeta, where \zeta=\left(\partial v_{y} / \partial x-\partial v_{x} / \partial y\right) is the vorticity, so that f acts as a source term for the vorticity. If f=0, the vorticity will be zero and there will be no rotation. But a positive value of f would mean that the vorticity is positive, corresponding to a counterclockwise rotation. And a negative value of f would indicate a clockwise rotation. Such rotations could result from the shear stresses induced on the surface of the lake by a nonuniform wind, whose velocity v_{y} varies with x as shown in Fig. E7.4.2. Note that in the eastern region (x>0) the intensity increases toward the east, and in the western region (x<0) the intensity increases toward the west.
Solve for the pattern of streamlines for each of the following three cases, using SI units throughout:
- The stream function equals \psi=0 along the near shore between points B and C and equals \psi=100 along the far shore between points D and A. From B to A and from C to D, \psi varies linearly from zero to 100 . Everywhere, f=0.
- The rivers are “turned off,” so the lake is now isolated and its boundary becomes the single streamline \psi=0. However, the vorticity source term is now f=2.5 \times 10^{-6} x \mathrm{~s}^{-1}. Thus, we would expect a counterclockwise rotation for x>0 and a clockwise rotation for x<0.
- Finally, consider the case of both river flow and the nonuniform wind. The boundary conditions will be the same as for Case 1, but the expression for f will be the same as for Case 2 .