For the machine part shown in Fig. (a), replace the applied load of 150 kN acting at point A by (1) an equivalent force-couple system with the force acting at point B; and (2) two horizontal forces, one acting at point B and the other acting at point C.

Question

Accepted Answer

Part 1

First we move the 150-kN force to point B, and then we introduce the couple of transfer equal to the moment of the 150-kN force in Fig. (a) about point B, given by

[latex]\underset{+}{\curvearrowleft }C^{T}=M_{B}=-150(0.080 + 0.040)=−18 kN · m[/latex]

The negative sign indicates that the sense of the couple is clockwise. The equivalent force-couple system is shown in Fig. (b).

Part 2

The 18 kN·m clockwise couple in Fig. (b) can be replaced by two 450-kN forces, one acting at point B and the other at point C, as shown in Fig. (c). (The couple represented by these two forces is 450(0.040)=18 kN ·m in the clockwise direction.) The two forces acting at point B can be added to get the system shown in Fig. (d). This is the answer, because we have replaced the original force with two horizontal forces, one at point B and the other at point C, as required.

Question 2.10: For the machine part shown in Fig. (a), replace the applied ...

Related Answered Questions