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Question 5.9: Heat of Fusion . The heat of fusion of ice is 80. cal/g. How...

Heat of Fusion . The heat of fusion of ice is 80. cal/g. How many calories are required to melt 1.0 mol of ice?

Strategy : We first convert moles of ice to grams of ice using the conversion factor 1 mol of ice = 18 g of ice. We then use the heat of fusion of ice (80. cal/g) to calculate the number of calories required to melt the given quantity of ice.

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1.0 mole of H_{2} O  has a mass of 18 g. We use the factor-label method to calculate the heat required to melt 1.0 mole of ice at 0°.

\frac{80. cal}{ 8\cancel {g ice}} \times 18\cancel {g ice}= 1.4 \times 10^{3} cal

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