Question 14.8: How many grams of potassium hydroxide are required to prepar...

How many grams of potassium hydroxide are required to prepare 600. mL of 0.450 M KOH  solution?

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Solution map:    milliliters→liters→moles→grams

PLAN        Knowns        volume = 600. mL       M= \frac{0.450   mol}{L}

molar mass KOH= \frac{56.11   g}{mol}

CALCULATE          (600.   \cancel{mL}) (\frac{1  \cancel{L}}{1000  \cancel{mL}} ) (\frac{0.450  \cancel{mol}}{\cancel{L}} ) (\frac{56.11   g    KOH}{\cancel{mol}} ) = 15.1 g  KOH

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