Question 10.17: I showed that at most one point on the particle trajectory c...

I showed that at most one point on the particle trajectory communicates with r at any given time. In some cases there may be no such point (an observer at r would not see the particle—in the colorful language of general relativity, it is “over the horizon”). As an example, consider a particle in hyperbolic motion along the x axis:

w (t)=\sqrt{b^{2}+(c t)^{2}} \hat{ x } \quad(-\infty<t<\infty) .                             (10.52)

(In special relativity, this is the trajectory of a particle subject to a constant force \left.F=m c^{2} / b .\right) Sketch the graph of w versus t. At four or five representative points on the curve, draw the trajectory of a light signal emitted by the particle at that point—both in the plus x direction and in the minus x direction. What region on your graph corresponds to points and times (x, t) from which the particle cannot be seen? At what time does someone at point x first see the particle? (Prior to this the potential at x is zero.) Is it possible for a particle, once seen, to disappear from view?

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Once seen, from a given point x, the particle will forever remain in view—to disappear it would have to travel faster than light.

10.17

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