Question 7.T-Y-S.F: In a chlorine-fluxing installation in a large aluminum compa...

In a chlorine-fluxing installation in a large aluminum company, engineers are considering the replacement of existing plastic pipe fittings with more expensive, but longer lived, copper fittings. The following table gives a comparison of the capital investments, lives, salvage values, and so on of the two mutually exclusive alternatives under consideration:

Plastic Copper
Capital investment $5,000 $10,000
Useful (class) life 5 years 10 years
Salvage value for depreciation purposes $1,000(=SV_{5} ) $5,000(=SV_{10} )
Annual expenses $300 $100
Market value at end of useful life $0 $0

Depreciation amounts are calculated with the SL method. Assume an income tax rate of 40 \% and a MARR after-taxes of 12 \% per year. Which pipe fitting would you select and why? Carefully list all assumptions that you make in performing the analysis. (7.9,7.10)

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Assume repeatability.

Alternative A: Plastic

d=(\$ 5,000-\$ 1,000) / 5=\$ 800
EOY (A)
BTCF
(B)
Depr.
(C) = (A) − (B)
TI
(D) = −t (C)
T (40%)
(E) = (A) + (D)
ATCF
0 −$5,000 − $5,000
1–5 −$300 $800 −$1,100 $440 $140
5 0 −$1,000 $400 $400
\operatorname{AW}_{\mathrm{A}}(12 \%)=-\$ 5,000(A / P, 12 \%, 5)+\$ 140+\$ 400(A / F, 12 \%, 5)=-\$ 1,184

Alternative B: Copper

d=(\$ 10,000-\$ 5,000) / 10=\$ 500
EOY (A)
BTCF
(B)
Depr.
(C) = (A) − (B)
TI
(D) = −t (C)
T (40%)
(E) = (A) + (D)
ATCF
0 −$10,000 −$10,000
1−10 −$100 $500 −$600 $240 $140
10 0 −$5,000 $2,000 $2,000
A W_{\mathrm{B}}(12 \%)=-\$ 10,000(A / P, 12 \%, 10)+\$ 140+\$ 2,000(A / F, 12 \%, 5)=-\$ 1,516

Select Alternative A: Plastic.

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