In Fig. 2-7 the areas of the plunger A and cylinder B are 6.00 and 600 in2, respectively, and the weight of B is 9000 Ib. The vessel and the connecting passages are filled with oil of specific gravity 0.750. What force F is required for equilibrium, neglecting the weight of A?

Question

In Fig. 2-7 the areas of the plunger A and cylinder B are 6.00 and 600 in², respectively, and the weight of B is 9000 Ib. The vessel and the connecting passages are filled with oil of specific gravity 0.750. What force F is required for equilibrium, neglecting the weight of A?

Accepted Answer

First determine the unit pressure acting on the plunger A. Since X_L and X_R are at the same level in the same liquid,

pressure at X_L in psi = pressure at X_R in psi

or pressure under A + pressure due to 16 ft oil = [latex] \frac{weight of B}{area of B} [/latex]

Substituting, [latex] p_{A}+\frac{\gamma h}{144} =\frac{9000 lb}{600 in^2} [/latex]

[latex] p_{A}+\frac{(0.750 imes 62.4)16}{144} psi =15.0 psi [/latex] and [latex] p_{A}=9.80 psi [/latex]

Force F = uniform pressure × area = 9.80 lb/in² × 6.00 in² = 58.8 Ib.

Question 2.13: In Fig. 2-7 the areas of the plunger A and cylinder B are 6....

This Question has been Answered.

Already have an account?

Login

Related Answered Questions