In Fig. 3-14, the 8-ft-diameter cylinder weighs 500 Ib and rests on the bottom of a tank that is 3 ft long. Water and oil are poured into the left- and right-hand portions of the tank to depths of 2 and 4 ft, respectively. Find the magnitudes of the horizontal and vertical components of the force t

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Accepted Answer

net [latex]F_{H}[/latex] = component on A B to left — component on C B to right

= [0.750 x 62.4 x 2(4 x 3)] – [62.4 x 1(2 x 3)] = 749 Ib to left

net [latex]F_{V}[/latex] = component upward on AB + component upward on CB

= weight of quadrant of oil + weight of (sector — triangle) of water

= (0.750 x 62.4 x 3 x [latex]\frac{1}{4}\pi 4^2 [/latex]) + {62.4 x 3 [[latex]\frac{1}{6}\pi 4^2 [/latex] – ([latex]\frac{1}{2} imes 2\sqrt{12} [/latex])]} = 2680 Ib upward

The components to hold the cylinder in place are 749 Ib to the right and 2180 Ib downward.

Question 3.15: In Fig. 3-14, the 8-ft-diameter cylinder weighs 500 Ib and r...

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